LeetCode 3280: Convert Date to Binary

Explanation:

To solve this problem, we need to convert the given Gregorian calendar date into its binary representation in the format of year-month-day. We can achieve this by first splitting the input date into year, month, and day components, converting each component into binary, and then joining them back in the required format.

1. Parse the input date string to extract year, month, and day components.
2. Convert each component into its binary representation without leading zeroes.
3. Join the binary representations of year, month, and day with hyphens to form the final output.

Time Complexity:

The time complexity of this solution is O(1) since the input date format is fixed.

Space Complexity:

The space complexity is also O(1) as we are not using any additional space that grows with the input size.

:

class Solution {
    public String convertDateToBinary(String date) {
        String[] parts = date.split("-");
        int year = Integer.parseInt(parts[0]);
        int month = Integer.parseInt(parts[1]);
        int day = Integer.parseInt(parts[2]);
        
        String binaryYear = Integer.toBinaryString(year);
        String binaryMonth = Integer.toBinaryString(month);
        String binaryDay = Integer.toBinaryString(day);
        
        return binaryYear + "-" + binaryMonth + "-" + binaryDay;
    }
}