LeetCode 3281: Maximize Score of Numbers in Ranges
Problem Description
Explanation:
-
Algorithmic Idea:
- Iterate through the given array of integers
startand calculate the possible choices of integers within each interval. - Sort all possible choices and calculate the absolute differences between consecutive choices to find the minimum absolute difference.
- Return this minimum absolute difference as the maximum possible score.
- Iterate through the given array of integers
-
Time Complexity: O(n log n) where n is the length of the
startarray due to sorting. -
Space Complexity: O(n) to store the possible choices.
Solutions
import java.util.Arrays;
class Solution {
public int maximizeScore(int[] start, int d) {
int n = start.length;
int[] choices = new int[n * 2];
for (int i = 0; i < n; i++) {
choices[i * 2] = start[i];
choices[i * 2 + 1] = start[i] + d;
}
Arrays.sort(choices);
int maxScore = Integer.MAX_VALUE;
for (int i = 1; i < choices.length; i++) {
maxScore = Math.min(maxScore, choices[i] - choices[i - 1]);
}
return maxScore;
}
}Loading editor...