LeetCode 2677: Chunk Array
LeetCode 2677 Solution Explanation
Explanation:
To chunk an array into subarrays of a specified size, we can iterate through the input array and create subarrays of the desired size. We keep track of the current chunk and add elements to it until it reaches the specified size or we exhaust all elements in the array. Each chunk formed is then added to the result list.
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Algorithm:
- Initialize an empty list to store the chunked arrays.
- Iterate through the input array:
- Create a new chunk list.
- Add elements to the chunk list until it reaches the specified size or we run out of elements.
- Add the chunk list to the result list.
- Return the list of chunked arrays.
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Time Complexity: O(n)
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Space Complexity: O(n)
:
LeetCode 2677 Solutions in Java, C++, Python
class Solution {
public List<List<Integer>> chunkArray(int[] arr, int size) {
List<List<Integer>> result = new ArrayList<>();
List<Integer> chunk = new ArrayList<>();
for (int num : arr) {
if (chunk.size() == size) {
result.add(new ArrayList<>(chunk));
chunk.clear();
}
chunk.add(num);
}
if (!chunk.isEmpty()) {
result.add(chunk);
}
return result;
}
}Interactive Code Editor for LeetCode 2677
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