2675. Array of Objects to Matrix
Explanation:
Given an array of objects, we need to convert it into a matrix where each row represents an object and each column represents a property of the object.
To achieve this, we can follow these steps:
- Get the list of properties from the first object to determine the number of columns in the matrix.
- Initialize a 2D matrix where the number of rows is the size of the input array and the number of columns is the number of properties.
- Iterate through the input array and populate the matrix by mapping each object to a row and each property to a column in the matrix.
The time complexity of this solution is O(n * m), where n is the number of objects in the input array, and m is the number of properties in each object. The space complexity is O(n * m) to store the resulting matrix.
:
import java.util.List;
public int[][] arrayToMatrix(List<Object> objects) {
if (objects == null || objects.isEmpty()) return new int[0][0];
int n = objects.size();
int m = objects.get(0).getClass().getDeclaredFields().length;
int[][] matrix = new int[n][m];
for (int i = 0; i < n; i++) {
Object obj = objects.get(i);
int j = 0;
for (java.lang.reflect.Field field : obj.getClass().getDeclaredFields()) {
field.setAccessible(true);
try {
matrix[i][j++] = field.getInt(obj);
} catch (IllegalAccessException e) {
e.printStackTrace();
}
}
}
return matrix;
}Code Editor (Testing phase)
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