LeetCode 876: Middle of the Linked List
LeetCode 876 Solution Explanation
Explanation
To find the middle node of a linked list, we can use the two-pointer approach. We will use two pointers, a slow pointer and a fast pointer. The slow pointer moves one step at a time while the fast pointer moves two steps at a time. When the fast pointer reaches the end of the list, the slow pointer will be at the middle node.
Algorithm:
- Initialize two pointers, slow and fast, pointing to the head of the linked list.
- Move slow pointer one step and fast pointer two steps at a time until the fast pointer reaches the end of the list.
- Return the node pointed by the slow pointer, which will be the middle node.
Time Complexity: O(N) where N is the number of nodes in the linked list. Space Complexity: O(1)
LeetCode 876 Solutions in Java, C++, Python
public ListNode middleNode(ListNode head) {
ListNode slow = head;
ListNode fast = head;
while (fast != null && fast.next != null) {
slow = slow.next;
fast = fast.next.next;
}
return slow;
}Interactive Code Editor for LeetCode 876
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