LeetCode 3315: Construct the Minimum Bitwise Array II
LeetCode 3315 Solution Explanation
Explanation
To solve this problem, we need to find an array ans such that for each index i, the bitwise OR of ans[i] and ans[i] + 1 equals nums[i]. We aim to minimize each value of ans[i] while satisfying this condition. If it's not possible, we set ans[i] = -1.
We can observe that for a given nums[i], we need to find the smallest number ans[i] such that ans[i] OR (ans[i] + 1) = nums[i]. This means that the highest unset bit in nums[i] should be set in ans[i] while keeping all lower-order bits unchanged. If there is no such number, we set ans[i] = -1`.
LeetCode 3315 Solutions in Java, C++, Python
class Solution {
public int[] minBitwiseArray(int[] nums) {
int n = nums.length;
int[] ans = new int[n];
for (int i = 0; i < n; i++) {
int highestBit = Integer.highestOneBit(nums[i]);
if ((highestBit | nums[i]) != (nums[i] + 1)) {
ans[i] = -1;
} else {
ans[i] = highestBit - 1;
}
}
return ans;
}
}Interactive Code Editor for LeetCode 3315
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