LeetCode 2903: Find Indices With Index and Value Difference I
LeetCode 2903 Solution Explanation
Explanation:
To solve this problem, we can iterate through all pairs of indices i and j and check if the conditions abs(i - j) >= indexDifference and abs(nums[i] - nums[j]) >= valueDifference are satisfied. If we find such a pair, we return the indices i and j. If no such pair exists, we return [-1, -1].
- Time Complexity: O(n^2) where n is the length of the input array nums.
- Space Complexity: O(1)
LeetCode 2903 Solutions in Java, C++, Python
class Solution {
public int[] findIndices(int[] nums, int indexDifference, int valueDifference) {
for (int i = 0; i < nums.length; i++) {
for (int j = 0; j < nums.length; j++) {
if (i != j && Math.abs(i - j) >= indexDifference && Math.abs(nums[i] - nums[j]) >= valueDifference) {
return new int[]{i, j};
}
}
}
return new int[]{-1, -1};
}
}Interactive Code Editor for LeetCode 2903
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