2562. Find the Array Concatenation Value
Explanation:
To solve this problem, we can use a greedy approach. We repeatedly find the first and last elements of the array, concatenate them, add the result to the total concatenation value, and remove these elements from the array. We continue this process until the array becomes empty.
Time Complexity:
The time complexity of this approach is O(N^2), where N is the number of elements in the input array.
Space Complexity:
The space complexity is O(N) for storing the input array.
class Solution {
public int getConcatenationValue(int[] nums) {
int concatValue = 0;
while (nums.length > 1) {
concatValue += Integer.parseInt(nums[0] + "" + nums[nums.length - 1]);
nums = Arrays.copyOfRange(nums, 1, nums.length - 1);
}
if (nums.length == 1) {
concatValue += nums[0];
}
return concatValue;
}
}Code Editor (Testing phase)
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