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2455. Average Value of Even Numbers That Are Divisible by Three

ArrayMath

Explanation:

To solve this problem, we iterate through the given array nums and check if each even number is divisible by 3. If it is, we add it to our running sum and keep track of the count of such numbers. Finally, we return the integer division of the sum by the count. If no even number is found that satisfies the condition, we return 0.

Algorithm:

  1. Initialize variables sum and count to 0.
  2. Iterate through each element num in the array nums.
  3. Check if num is even and divisible by 3.
  4. If the condition is satisfied, add num to sum and increment count.
  5. After iterating through all elements, return sum / count if count is greater than 0, else return 0.

Time Complexity: O(n), where n is the number of elements in the input array. Space Complexity: O(1)

:

View Leetcode Problem
class Solution {
    public int averageEvenDivByThree(int[] nums) {
        int sum = 0;
        int count = 0;
        
        for (int num : nums) {
            if (num % 2 == 0 && num % 3 == 0) {
                sum += num;
                count++;
            }
        }
        
        return count > 0 ? sum / count : 0;
    }
}

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