LeetCode 2413: Smallest Even Multiple
LeetCode 2413 Solution Explanation
Explanation:
To find the smallest positive integer that is a multiple of both 2 and n, we can simply multiply n by 2 if n is already even, or multiply n by 2 until it becomes even. This is because any multiple of n will also be a multiple of 2 if n is even.
- Initialize a variable
resultto n. - If n is odd, multiply n by 2 until it becomes even.
- Return the result.
Time Complexity:
The time complexity of this solution is O(log n) because we might need to multiply n by 2 multiple times to make it even.
Space Complexity:
The space complexity of this solution is O(1) as we are using only a constant amount of extra space.
:
LeetCode 2413 Solutions in Java, C++, Python
class Solution {
public int smallestEvenMultiple(int n) {
int result = n;
while (result % 2 != 0) {
result *= 2;
}
return result;
}
}Interactive Code Editor for LeetCode 2413
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