LeetCode 2410: Maximum Matching of Players With Trainers
LeetCode 2410 Solution Explanation
Explanation:
To maximize the number of matchings between players and trainers, we can sort both the players and trainers arrays in ascending order. Then, we can iterate through the sorted arrays and try to match players with trainers based on their abilities and training capacities. If a player's ability is less than or equal to a trainer's training capacity, we can increment the count of matchings and move on to the next player. This greedy approach ensures that we make the best possible matchings.
Algorithm:
- Sort the players and trainers arrays in ascending order.
- Initialize variables
matchingCountto store the number of matchings andtrainerIndexto keep track of the current trainer being considered. - Iterate through the players array and for each player, iterate through the trainers array starting from the
trainerIndex. - If a player can be matched with a trainer, increment
matchingCountand updatetrainerIndexto move to the next trainer. - Return the
matchingCountas the maximum number of matchings.
Time Complexity: O(n log n), where n is the total number of players and trainers combined due to sorting.
Space Complexity: O(1) as we are using a constant amount of extra space.
:
LeetCode 2410 Solutions in Java, C++, Python
class Solution {
public int maxMatchings(int[] players, int[] trainers) {
Arrays.sort(players);
Arrays.sort(trainers);
int matchingCount = 0;
int trainerIndex = 0;
for (int player : players) {
while (trainerIndex < trainers.length && trainers[trainerIndex] < player) {
trainerIndex++;
}
if (trainerIndex < trainers.length) {
matchingCount++;
trainerIndex++;
}
}
return matchingCount;
}
}Interactive Code Editor for LeetCode 2410
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