LeetCode 1802: Maximum Value at a Given Index in a Bounded Array
LeetCode 1802 Solution Explanation
Explanation:
To maximize the value at the given index while satisfying the constraints, we can use binary search to find the maximum possible value at that index. We can then calculate the sum of the elements before and after the index to ensure that the total sum does not exceed maxSum. Based on this, we adjust the binary search range accordingly.
- Perform binary search to find the maximum value at the given index.
- Calculate the sum of elements before and after the index.
- Adjust the binary search range based on the total sum.
- Return the maximum value at the given index.
Time Complexity: O(log(maxSum)) Space Complexity: O(1)
:
LeetCode 1802 Solutions in Java, C++, Python
class Solution {
public int maxValue(int n, int index, int maxSum) {
int left = 1, right = maxSum;
while (left < right) {
int mid = left + (right - left) / 2;
long sum = calculateSum(n, index, mid);
if (sum < maxSum) {
left = mid + 1;
} else {
right = mid;
}
}
return left;
}
private long calculateSum(int n, int index, int num) {
long sum = num;
int left = Math.min(index, num - 1);
int right = Math.min(n - index - 1, num - 1);
sum += (long)left * (left + 1) / 2 + (long)right * (right + 1) / 2;
return sum;
}
}Interactive Code Editor for LeetCode 1802
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