1788. Maximize the Beauty of the Garden
Explanation
The problem asks us to find the maximum beauty of a garden by rearranging its flowers. The beauty of the garden is calculated as the sum of the beauty of its flowers multiplied by their positions. We need to rearrange the flowers in such a way that the beauty is maximized.
To solve this problem, we can follow the following approach:
- Calculate the initial beauty of the garden.
- Iterate over all possible pairs of flowers and calculate the beauty if we swap these two flowers.
- Update the maximum beauty if the new beauty after swapping is greater.
- Repeat step 2 and 3 until we have considered all possible pairs.
The time complexity of this approach is O(N^2) where N is the number of flowers in the garden. The space complexity is O(1) as we are not using any extra space.
class Solution {
public int maxBeauty(int[] flowers) {
int n = flowers.length;
int maxBeauty = Integer.MIN_VALUE;
int initialBeauty = 0;
for (int i = 0; i < n; i++) {
initialBeauty += flowers[i];
if (i > 0) {
initialBeauty -= Math.max(0, flowers[i] - flowers[i - 1]);
}
}
maxBeauty = Math.max(maxBeauty, initialBeauty);
for (int i = 0; i < n; i++) {
for (int j = i + 1; j < n; j++) {
int newBeauty = initialBeauty;
if (j > i + 1) {
newBeauty -= Math.max(0, flowers[j] - flowers[j - 1]);
}
if (j < n - 1) {
newBeauty -= Math.max(0, flowers[j + 1] - flowers[j]);
}
newBeauty += Math.max(0, flowers[j] - flowers[i]);
maxBeauty = Math.max(maxBeauty, newBeauty);
}
}
return maxBeauty;
}
}Code Editor (Testing phase)
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