LeetCode 1748: Sum of Unique Elements
LeetCode 1748 Solution Explanation
Explanation
To solve this problem, we can use a hashmap to keep track of the frequency of each element in the input array. Then, we iterate over the hashmap and sum up the unique elements (elements with frequency 1). Finally, we return the total sum.
-
Algorithm:
- Initialize a hashmap to store the frequency of each element.
- Iterate over the input array and update the frequency in the hashmap.
- Iterate over the hashmap and sum up the unique elements.
- Return the total sum.
-
Time Complexity: O(n) where n is the number of elements in the input array.
-
Space Complexity: O(n) for the hashmap.
LeetCode 1748 Solutions in Java, C++, Python
class Solution {
public int sumOfUnique(int[] nums) {
Map<Integer, Integer> frequencyMap = new HashMap<>();
int sum = 0;
for (int num : nums) {
frequencyMap.put(num, frequencyMap.getOrDefault(num, 0) + 1);
}
for (int key : frequencyMap.keySet()) {
if (frequencyMap.get(key) == 1) {
sum += key;
}
}
return sum;
}
}Interactive Code Editor for LeetCode 1748
Improve Your LeetCode 1748 Solution
Use the editor below to refine the provided solution for LeetCode 1748. Select a programming language and try the following:
- Add import statements if required.
- Optimize the code for better time or space complexity.
- Add test cases to validate edge cases and common scenarios.
- Handle error conditions or invalid inputs gracefully.
- Experiment with alternative approaches to deepen your understanding.
Click "Run Code" to execute your solution and view the output. If errors occur, check the line numbers and debug accordingly. Resize the editor by dragging its bottom edge.
Loading editor...