LeetCode 1742: Maximum Number of Balls in a Box
LeetCode 1742 Solution Explanation
Explanation
To solve this problem, we need to count the number of balls that would go into each box based on the sum of the digits of the ball numbers in the given range [lowLimit, highLimit]. We can iterate through each ball number, compute the sum of its digits, and increment the count for the corresponding box. Finally, we find the box with the maximum number of balls.
- Initialize a HashMap to store the count of balls in each box.
- Iterate through each ball number in the range [lowLimit, highLimit].
- For each ball number, compute the sum of its digits.
- Increment the count for the corresponding box in the HashMap.
- Find the box with the maximum number of balls.
- Return the count of balls in the box with the maximum count.
Time Complexity: O(n * log(highLimit)) where n is the number of balls and log(highLimit) is the maximum number of digits in any ball number. Space Complexity: O(n) for the HashMap to store the count of balls in each box.
LeetCode 1742 Solutions in Java, C++, Python
class Solution {
public int countBalls(int lowLimit, int highLimit) {
Map<Integer, Integer> boxCount = new HashMap<>();
int maxCount = 0;
for (int i = lowLimit; i <= highLimit; i++) {
int sum = 0;
int num = i;
while (num > 0) {
sum += num % 10;
num /= 10;
}
boxCount.put(sum, boxCount.getOrDefault(sum, 0) + 1);
maxCount = Math.max(maxCount, boxCount.get(sum));
}
return maxCount;
}
}Interactive Code Editor for LeetCode 1742
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