LeetCode 169: Majority Element
LeetCode 169 Solution Explanation
Explanation:
To find the majority element in an array, we can use the Boyer-Moore Voting Algorithm. The idea is to cancel out each occurrence of a majority element with all other elements. If there is a majority element in the array, it will be left as the last candidate after all the elements are processed.
Algorithm:
- Initialize a variable
candidateto store the current candidate for the majority element and a variablecountto keep track of its frequency. - Iterate through the array:
- If the count is 0, set the current element as the candidate and increment the count.
- If the current element is the same as the candidate, increment the count; otherwise, decrement the count.
- The majority element will be the last remaining candidate.
Time Complexity: O(n) Space Complexity: O(1)
:
LeetCode 169 Solutions in Java, C++, Python
class Solution {
public int majorityElement(int[] nums) {
int candidate = 0, count = 0;
for (int num : nums) {
if (count == 0) {
candidate = num;
}
count += (num == candidate) ? 1 : -1;
}
return candidate;
}
}Interactive Code Editor for LeetCode 169
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