LeetCode 1636: Sort Array by Increasing Frequency
LeetCode 1636 Solution Explanation
Explanation
To solve this problem, we can follow these steps:
- Create a frequency map to store the frequency of each element in the input array.
- Sort the array based on the frequency of elements in increasing order. If two elements have the same frequency, sort them in decreasing order.
- Implement a custom comparator to sort the elements based on the above criteria.
- Finally, return the sorted array.
Time complexity: O(n log n)
Space complexity: O(n)
LeetCode 1636 Solutions in Java, C++, Python
class Solution {
public int[] frequencySort(int[] nums) {
Map<Integer, Integer> freqMap = new HashMap<>();
for (int num : nums) {
freqMap.put(num, freqMap.getOrDefault(num, 0) + 1);
}
Arrays.sort(nums, (a, b) -> freqMap.get(a).equals(freqMap.get(b)) ? b - a : freqMap.get(a) - freqMap.get(b));
return nums;
}
}Interactive Code Editor for LeetCode 1636
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