LeetCode 1588: Sum of All Odd Length Subarrays
LeetCode 1588 Solution Explanation
Explanation:
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Algorithmic Idea:
- For each element in the array, we calculate the number of subarrays it can contribute to with odd length.
- The number of subarrays an element at index
ican contribute to is(i + 1) * (n - i)wherenis the length of the array. - We iterate through the array, calculate the sum of each element multiplied by the number of subarrays it can contribute to, and sum them up.
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Time Complexity: O(n)
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Space Complexity: O(1)
:
LeetCode 1588 Solutions in Java, C++, Python
class Solution {
public int sumOddLengthSubarrays(int[] arr) {
int sum = 0;
int n = arr.length;
for (int i = 0; i < n; i++) {
int contribution = (i + 1) * (n - i);
sum += (contribution + 1) / 2 * arr[i];
}
return sum;
}
}Interactive Code Editor for LeetCode 1588
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