How to solve LeetCode 1255 (Maximum Score Words Formed by Letters)?

This page provides optimized solutions for LeetCode problem 1255 (Maximum Score Words Formed by Letters) in Java, C++, and Python, along with a detailed explanation and an interactive code editor to test and refine your code.

LeetCode 1255: Maximum Score Words Formed by Letters Solution

LeetCode 1255 Solution Explanation

Explanation:

To solve this problem, we can use a brute force approach with backtracking. We will iterate through all possible subsets of words, checking if we can form each subset using the given letters. For each valid subset, we calculate the score and keep track of the maximum score found so far.

Algorithm:

Create a frequency map of the available letters.
Generate all possible subsets of words.
For each subset:
- Check if we can form the subset using the available letters.
- If we can, calculate the score of the subset and update the maximum score if needed.
Return the maximum score found.

Time Complexity:

The time complexity of this approach is O(2^N) where N is the number of words in the input list.

Space Complexity:

The space complexity is O(1) for the frequency map and O(N) for the recursion stack. :

LeetCode 1255 Solutions in Java, C++, Python

class Solution {
    public int maxScoreWords(String[] words, char[] letters, int[] score) {
        int[] letterFreq = new int[26];
        for (char c : letters) {
            letterFreq[c - 'a']++;
        }
        return backtrack(words, letterFreq, score, 0);
    }

    private int backtrack(String[] words, int[] letterFreq, int[] score, int index) {
        if (index == words.length) {
            return 0;
        }

        int scoreWithout = backtrack(words, letterFreq.clone(), score, index + 1);
        int scoreWith = 0;
        String word = words[index];
        boolean valid = true;
        for (char c : word.toCharArray()) {
            if (letterFreq[c - 'a'] == 0) {
                valid = false;
            }
            letterFreq[c - 'a']--;
            scoreWith += score[c - 'a'];
        }
        if (valid) {
            scoreWith += backtrack(words, letterFreq, score, index + 1);
        }

        return Math.max(scoreWith, scoreWithout);
    }
}

Interactive Code Editor for LeetCode 1255

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